№4
Выполните действия
- a) $$9 \frac{8}{14} + 3 \frac{11}{14} = (9 + 3) + (\frac{8}{14} + \frac{11}{14}) = 12 + \frac{19}{14} = 12 + \frac{14 + 5}{14} = 12 + 1 + \frac{5}{14} = 13 \frac{5}{14}$$
- б) $$8 - 2 \frac{3}{8} = 7 \frac{8}{8} - 2 \frac{3}{8} = (7-2) + (\frac{8}{8} - \frac{3}{8}) = 5 \frac{5}{8}$$
- в) $$11 - 5 \frac{12}{16} = 10 \frac{16}{16} - 5 \frac{12}{16} = (10 - 5) + (\frac{16}{16} - \frac{12}{16}) = 5 \frac{4}{16} = 5 \frac{1}{4}$$
- 2) $$12 \frac{13}{20} - 7 \frac{8}{20} = (12 - 7) + (\frac{13}{20} - \frac{8}{20}) = 5 + \frac{5}{20} = 5 \frac{5}{20} = 5 \frac{1}{4}$$
- 8) $$6 \frac{2}{7} - 4 \frac{4}{7} = 5 \frac{7}{7} + \frac{2}{7} - 4 \frac{4}{7} = 5 \frac{9}{7} - 4 \frac{4}{7} = (5 - 4) + (\frac{9}{7} - \frac{4}{7}) = 1 + \frac{5}{7} = 1 \frac{5}{7}$$
- e) $$8 \frac{5}{9} - 6 \frac{8}{9} = 7 \frac{9}{9} + \frac{5}{9} - 6 \frac{8}{9} = 7 \frac{14}{9} - 6 \frac{8}{9} = (7 - 6) + (\frac{14}{9} - \frac{8}{9}) = 1 + \frac{6}{9} = 1 \frac{6}{9} = 1 \frac{2}{3}$$
№5
Выразите действие
$$(18 \frac{3}{11} - 6) - (4 + 3 \frac{9}{11}) = 18 \frac{3}{11} - 6 - 4 - 3 \frac{9}{11} = (18 - 6 - 4 - 3) + (\frac{3}{11} - \frac{9}{11}) = 5 - \frac{6}{11} = 4 \frac{11}{11} - \frac{6}{11} = 4 \frac{5}{11}$$
Ответ: a) $$13 \frac{5}{14}$$, б) $$5 \frac{5}{8}$$, в) $$5 \frac{1}{4}$$, 2) $$5 \frac{1}{4}$$, 8) $$1 \frac{5}{7}$$, e) $$1 \frac{2}{3}$$, №5: $$4 \frac{5}{11}$$