66. Обратить в неправильные дроби следующие числа: 1\frac{1}{2}; 1\frac{2}{3}; 4\frac{2}{7}; 8\frac{5}{13}; 31\frac{5}{6}; 105\frac{3}{4}; 17\frac{11}{40}; 83\frac{7}{11}; 25\frac{19}{36}; 3\frac{1}{3}; 2\frac{3}{4}; 3\frac{4}{7}; 9\frac{4}{15}; 20\frac{3}{10}; 116\frac{2}{3}; 98\frac{17}{25}; 3\frac{1}{5}; 3\frac{5}{8}; 5\frac{11}{12}; 18\frac{5}{16}; 32\frac{3}{7};

Ответ: Преобразованные в неправильные дроби числа: \(\frac{3}{2}; \frac{5}{3}; \frac{30}{7}; \frac{109}{13}; \frac{191}{6}; \frac{423}{4}; \frac{691}{40}; \frac{920}{11}; \frac{919}{36}; \frac{10}{3}; \frac{11}{4}; \frac{25}{7}; \frac{139}{15}; \frac{203}{10}; \frac{350}{3}; \frac{2467}{25}; \frac{16}{5}; \frac{29}{8}; \frac{71}{12}; \frac{293}{16}; \frac{227}{7}\)

Преобразуем каждое число в неправильную дробь:

• \(1\frac{1}{2} = \frac{1 \cdot 2 + 1}{2} = \frac{3}{2}\)
• \(1\frac{2}{3} = \frac{1 \cdot 3 + 2}{3} = \frac{5}{3}\)
• \(4\frac{2}{7} = \frac{4 \cdot 7 + 2}{7} = \frac{30}{7}\)
• \(8\frac{5}{13} = \frac{8 \cdot 13 + 5}{13} = \frac{109}{13}\)
• \(31\frac{5}{6} = \frac{31 \cdot 6 + 5}{6} = \frac{191}{6}\)
• \(105\frac{3}{4} = \frac{105 \cdot 4 + 3}{4} = \frac{423}{4}\)
• \(17\frac{11}{40} = \frac{17 \cdot 40 + 11}{40} = \frac{691}{40}\)
• \(83\frac{7}{11} = \frac{83 \cdot 11 + 7}{11} = \frac{920}{11}\)
• \(25\frac{19}{36} = \frac{25 \cdot 36 + 19}{36} = \frac{919}{36}\)
• \(3\frac{1}{3} = \frac{3 \cdot 3 + 1}{3} = \frac{10}{3}\)
• \(2\frac{3}{4} = \frac{2 \cdot 4 + 3}{4} = \frac{11}{4}\)
• \(3\frac{4}{7} = \frac{3 \cdot 7 + 4}{7} = \frac{25}{7}\)
• \(9\frac{4}{15} = \frac{9 \cdot 15 + 4}{15} = \frac{139}{15}\)
• \(20\frac{3}{10} = \frac{20 \cdot 10 + 3}{10} = \frac{203}{10}\)
• \(116\frac{2}{3} = \frac{116 \cdot 3 + 2}{3} = \frac{350}{3}\)
• \(98\frac{17}{25} = \frac{98 \cdot 25 + 17}{25} = \frac{2467}{25}\)
• \(3\frac{1}{5} = \frac{3 \cdot 5 + 1}{5} = \frac{16}{5}\)
• \(3\frac{5}{8} = \frac{3 \cdot 8 + 5}{8} = \frac{29}{8}\)
• \(5\frac{11}{12} = \frac{5 \cdot 12 + 11}{12} = \frac{71}{12}\)
• \(18\frac{5}{16} = \frac{18 \cdot 16 + 5}{16} = \frac{293}{16}\)
• \(32\frac{3}{7} = \frac{32 \cdot 7 + 3}{7} = \frac{227}{7}\)

Ответ: Преобразованные в неправильные дроби числа: \(\frac{3}{2}; \frac{5}{3}; \frac{30}{7}; \frac{109}{13}; \frac{191}{6}; \frac{423}{4}; \frac{691}{40}; \frac{920}{11}; \frac{919}{36}; \frac{10}{3}; \frac{11}{4}; \frac{25}{7}; \frac{139}{15}; \frac{203}{10}; \frac{350}{3}; \frac{2467}{25}; \frac{16}{5}; \frac{29}{8}; \frac{71}{12}; \frac{293}{16}; \frac{227}{7}\)