\[ -\frac{25}{7} + \frac{22}{7} \cdot \left( \frac{33}{8} - \left( -\frac{9}{2} \right) \right) : \left( \frac{9}{20} \right) \]
\[ \frac{33}{8} + \frac{9 · 4}{2 · 4} = \frac{33}{8} + \frac{36}{8} = \frac{33+36}{8} = \frac{69}{8} \]
\[ -\frac{25}{7} + \frac{22}{7} \cdot \frac{69}{8} : \frac{9}{20} \]
\[ \frac{69}{8} : \frac{9}{20} = \frac{69}{8} \cdot \frac{20}{9} \]
Сократим дроби:\[ \frac{69}{8} \cdot \frac{20}{9} = \frac{69^3}{8^2} \cdot \frac{20^5}{9^3} = \frac{23 · 5}{2 · 3} = \frac{115}{6} \]
\[ \frac{22}{7} \cdot \frac{115}{6} = \frac{22^11}{7} \cdot \frac{115}{6^3} = \frac{11 · 115}{7 · 3} = \frac{1265}{21} \]
\[ -\frac{25}{7} + \frac{1265}{21} \]
Приведем к общему знаменателю 21:\[ -\frac{25 · 3}{7 · 3} + \frac{1265}{21} = -\frac{75}{21} + \frac{1265}{21} = \frac{-75+1265}{21} = \frac{1190}{21} \]
\[ \frac{1190}{21} = \frac{1190^170}{21^3} = \frac{170}{3} \]
\[ \frac{170}{3} = 56 \frac{2}{3} \]
Ответ: 56 \(\frac{2}{3}\)