Ответ:
\[B\left( \frac{1}{2}; - \frac{\sqrt{3}}{2} \right);\ \ C\left( - \frac{1}{2};\ - \frac{\sqrt{3}}{2} \right);\ \ \]
\[\alpha = \frac{10\pi}{6} = \frac{2\pi}{3};\ \ \beta = \frac{8\pi}{6} = \frac{4\pi}{3}.\]
\[B\left( \frac{1}{2}; - \frac{\sqrt{3}}{2} \right);\ \ C\left( - \frac{1}{2};\ - \frac{\sqrt{3}}{2} \right);\ \ \]
\[\alpha = \frac{10\pi}{6} = \frac{2\pi}{3};\ \ \beta = \frac{8\pi}{6} = \frac{4\pi}{3}.\]