\[ (b+4)^2 - b^2 - 4 = (b^2 + 8b + 16) - b^2 - 4 \]
\[ b^2 + 8b + 16 - b^2 - 4 = 8b + 12 \]
\[ 8 \cdot \frac{7}{8} + 12 \]
\[ 7 + 12 = 19 \]
Ответ: 19