Ответ:
Решение:
- a) \( \frac{5}{12} : \frac{10}{3} - \frac{5}{6} \cdot \frac{2}{15} = \frac{5}{12} \cdot \frac{3}{10} - \frac{5 \cdot 2}{6 \cdot 15} = \frac{5 \cdot 3}{12 \cdot 10} - \frac{10}{90} = \frac{15}{120} - \frac{1}{9} = \frac{1}{8} - \frac{1}{9} = \frac{9 - 8}{72} = \frac{1}{72} \)
- б) \( \frac{4}{25} \cdot \frac{5}{16} + \frac{7}{16} \cdot \frac{4}{5} = \frac{4 \cdot 5}{25 \cdot 16} + \frac{7 \cdot 4}{16 \cdot 5} = \frac{20}{400} + \frac{28}{80} = \frac{1}{20} + \frac{7}{20} = \frac{1 + 7}{20} = \frac{8}{20} = \frac{2}{5} \)
- в) \( \frac{9}{8} : \frac{5}{8} : \frac{3}{10} = \frac{9}{8} \cdot \frac{8}{5} \cdot \frac{10}{3} = \frac{9 \cdot 8 \cdot 10}{8 \cdot 5 \cdot 3} = \frac{9 \cdot 10}{5 \cdot 3} = \frac{90}{15} = 6 \)
Ответ: a) \( \frac{1}{72} \); б) \( \frac{2}{5} \); в) 6.
