A1. Correct answer: 2. The electronic configuration of magnesium (atomic number 12) is 1s²2s²2p⁶3s².
A2. Correct answer: 1. Metallic properties increase from right to left and from top to bottom in the periodic table. The order Na, Mg, Al shows increasing metallic properties.
A3. Correct answer: 2. Copper has the highest electrical conductivity among the given options.
A4. Correct answer: 1. Potassium is an alkali metal and reacts vigorously with water.
A5. Correct answer: 1. Zinc hydroxide is an amphoteric hydroxide and reacts with acids (HCl) and acidic oxides (CO₂).
A6. Correct answer: 2. Pyrometallurgy involves processing ores at high temperatures.
B1. Let's establish the correspondence:
A) CaO + CO₂ → CaCO₃ (or Ca(HCO₃)₂ if water is present, but CaCO₃ is the main product of the reaction between a basic oxide and an acidic oxide). The closest option is 6) CaCO₃.
Б) Ca(OH)₂ + SO₂ → CaSO₃ + H₂O. This corresponds to option 5).
B) Ca + H₂O → Ca(OH)₂ + H₂. This corresponds to option 4).
Г) Ca(HCO₃)₂ + Ca(OH)₂ → 2CaCO₃ + 2H₂O. This corresponds to option 6).
In cases where there are multiple correct options or ambiguity, we will select the most direct and common reaction. For A, typically the formation of a carbonate. For Г, the formation of carbonate is the primary reaction.
| A | Б | B | Г | |
|---|---|---|---|---|
| PRODUCT OF REACTION | 6 | 5 | 4 | 6 |
The resulting sequence is 6546.
C1. Let's write the reaction equations:
C2. Calculation of the volumetric yield of hydrogen:
First, let's determine the mass of pure magnesium:
Mass of impurities = 12 g * 5% = 0.6 g
Mass of pure Mg = 12 g - 0.6 g = 11.4 g
Now, let's find the moles of pure magnesium:
Molar mass of Mg = 24.305 g/mol
\[ n(Mg) = \frac{11.4 \text{ g}}{24.305 \text{ g/mol}} \approx 0.469 \text{ mol} \]
The reaction of magnesium with hydrochloric acid is:
\[ Mg + 2HCl \rightarrow MgCl_2 + H_2 \]
From the stoichiometry, 1 mole of Mg produces 1 mole of H₂. So, the theoretical moles of H₂ produced are approximately 0.469 mol.
Now, let's calculate the theoretical volume of H₂ at standard conditions (n.u. - normal conditions, usually taken as 0 °C and 1 atm, where molar volume is 22.4 L/mol):
\[ V_{\text{theoretical}}(H_2) = 0.469 \text{ mol} \times 22.4 \text{ L/mol} \approx 10.5056 \text{ L} \]
The actual volume of H₂ released is given as 10 L.
The volumetric yield of the reaction product is calculated as:
\[ \text{Yield} = \frac{\text{Actual Volume}}{\text{Theoretical Volume}} \times 100\% \]
\[ \text{Yield} = \frac{10 \text{ L}}{10.5056 \text{ L}} \times 100\% \approx 95.19\% \]
Ответ:
A1: 2
A2: 1
A3: 2
A4: 1
A5: 1
A6: 2
B1: 6546
C1:
C2. Объемная доля выхода продукта реакции составляет приблизительно 95.19%.