Вопрос:

Part C. 2. What distance can a car travel after refueling if it consumes 10 kg of gasoline per 100 km of travel, and the volume of the fuel tank is 60 liters. The density of gasoline is 710 kg/m³?

Ответ:

Solution:

First, we need to find the total mass of gasoline in the fuel tank. We are given the volume of the fuel tank and the density of gasoline.

Volume \( V = 60 \) liters. Since 1 liter = 0.001 m³, \( V = 60 \cdot 0.001 = 0.06 \) m³.

Density \( \rho = 710 \) kg/m³.

The mass \( m \) of gasoline can be calculated using the formula \( m = \rho \cdot V \).

\( m = 710 \) kg/m³ \( \cdot 0.06 \) m³ = \( 42.6 \) kg.

Now we know that the car consumes 10 kg of gasoline per 100 km. We need to find out how far it can travel with 42.6 kg of gasoline.

Let \( d \) be the distance the car can travel. We can set up a proportion:

\( \frac{10 \text{ kg}}{100 \text{ km}} = \frac{42.6 \text{ kg}}{d \text{ km}} \)

Now, we solve for \( d \):

\( d = \frac{42.6 \text{ kg} \cdot 100 \text{ km}}{10 \text{ kg}} \)

\( d = 42.6 \cdot 10 \text{ km} \)

\( d = 426 \) km.

Ответ: Автомобиль может проехать 426 км.

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