Perform the addition or subtraction:

Решение:

1. \( \frac{14}{19} + \frac{5}{19} = \frac{14+5}{19} = \frac{19}{19} = 1 \)
2. \( 4 \frac{11}{17} + 2 \frac{6}{17} = (4+2) + (\frac{11}{17} + \frac{6}{17}) = 6 + \frac{17}{17} = 6 + 1 = 7 \)
3. \( 5 + 3 \frac{3}{41} = 8 \frac{3}{41} \)
4. \( 2 \frac{1}{3} + 5 \frac{2}{3} = (2+5) + (\frac{1}{3} + \frac{2}{3}) = 7 + \frac{3}{3} = 7 + 1 = 8 \)
5. \( \frac{7}{34} + \frac{5}{34} = \frac{7+5}{34} = \frac{12}{34} = \frac{6}{17} \)
6. \( \frac{12}{41} - \frac{5}{41} = \frac{12-5}{41} = \frac{7}{41} \)
7. \( 16 - 9 \frac{6}{13} = 15 \frac{13}{13} - 9 \frac{6}{13} = (15-9) + (\frac{13}{13} - \frac{6}{13}) = 6 + \frac{7}{13} = 6 \frac{7}{13} \)
8. \( 7 + 4 \frac{3}{4} = 11 \frac{3}{4} \)
9. \( 12 \frac{1}{3} - 5 \frac{2}{3} = 11 \frac{4}{3} - 5 \frac{2}{3} = (11-5) + (\frac{4}{3} - \frac{2}{3}) = 6 + \frac{2}{3} = 6 \frac{2}{3} \)