\[\frac{2x + 3}{3} = \frac{7x + 12}{15} + \frac{x - 1}{5}\ \ | \cdot 15\]
\[5(2x + 3) = 7x + 12 + 3(x - 1)\]
\[10x + 15 = 7x + 12 + 3x - 3\]
\[10x - 10x = 9 - 15\]
\[0x = - 6.\]
\[Нет\ корней.\]