Вопрос:

posits the first column, pick the corresponding position of the second and write the chosen digits under the corresponding letters. Physical quantity A) internal energy of steam B) internal energy of water B) water temperature Answer: A B B.2 Establish the correspondence between devices and physical quantities that underlie their operation. For each position in the first column, choose the corresponding position in the second and write the chosen digits under the corresponding letters. Device A) Compass B) Electrometer B) Electric motor Answer: A B B C.1 What is the current strength in a nichrome conductor of length 12 m and cross-section 4 mm², on which a voltage of 36 mV is applied? (The specific resistance of steel is 0.4 Ohm mm²/m.

Ответ:

Exercise B.1

Instructions: Match the physical quantities in the first column with the character of their change in the second column. Write the chosen letters under the corresponding numbers in the table.

Matching:

Physical QuantityCharacter of Change
A) Internal energy of steam2) Increases
B) Internal energy of water2) Increases
B) Water temperature2) Increases

Answer Table:

ABB
222

Exercise B.2

Instructions: Match the devices in the first column with the physical phenomena that underlie their operation. For each position in the first column, choose the corresponding position in the second and write the chosen digits under the corresponding letters.

Matching:

DevicePhysical Phenomena
A) Compass1) Interaction of permanent magnets
B) Electrometer3) Electrization of bodies upon impact
B) Electric motor5) Effect of a magnetic field on a current-carrying conductor

Answer Table:

ABB
135

Exercise C.1

Problem: What is the current strength in a nichrome conductor of length 12 m and cross-section 4 mm², on which a voltage of 36 mV is applied? (The specific resistance of steel is 0.4 Ohm mm²/m.

Given:

  • Length, $$l = 12$$ m
  • Cross-sectional area, $$S = 4$$ mm²
  • Voltage, $$U = 36$$ mV
  • Specific resistance, $$\rho = 0.4$$ Ohm·mm²/m

Solution:

  1. Convert units to SI:
    • Voltage: $$U = 36 \text{ mV} = 36 \times 10^{-3} \text{ V}$$
  2. Calculate the resistance of the conductor using the formula: $$R = \rho \frac{l}{S}$$
    • $$R = 0.4 \frac{\text{Ohm} \times \text{mm}^2}{\text{m}} \times \frac{12 \text{ m}}{4 \text{ mm}^2}$$
    • $$R = 0.4 \times 3$$ Ohm
    • $$R = 1.2$$ Ohm
  3. Calculate the current strength using Ohm's Law: $$I = \frac{U}{R}$$
    • $$I = \frac{36 \times 10^{-3} \text{ V}}{1.2 \text{ Ohm}}$$
    • $$I = 30 \times 10^{-3}$$ A
    • $$I = 0.03$$ A

Answer: The current strength is 0.03 A.

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