Ответ:
\[f(x) = x^{2} + 2x - 3\]
\[x_{0} = \frac{- 2}{2} = - 1;\text{\ y}_{0} = - 4\]
| \[x\] | \[0\] | \[1\] |
|---|---|---|
| \[y\] | \[- 3\] | \[0\] |

\[y_{наим} = - 4;\ \ \]
\[y_{наиб} - не\ существует.\]
\[f(x) = x^{2} + 2x - 3\]
\[x_{0} = \frac{- 2}{2} = - 1;\text{\ y}_{0} = - 4\]
| \[x\] | \[0\] | \[1\] |
|---|---|---|
| \[y\] | \[- 3\] | \[0\] |

\[y_{наим} = - 4;\ \ \]
\[y_{наиб} - не\ существует.\]