Ответ:
\[y = \sqrt{x^{2}} + x - 2,\ если\ x \geq 0\]
\[y = \sqrt{x^{2}} + x - 2 =\]
\[= x + x - 2 = 2x - 2\]
| \[x\] | \[0\] | \[1\] |
|---|---|---|
| \[y\] | \[- 2\] | \[0\] |

\[y = \sqrt{x^{2}} + x - 2,\ если\ x \geq 0\]
\[y = \sqrt{x^{2}} + x - 2 =\]
\[= x + x - 2 = 2x - 2\]
| \[x\] | \[0\] | \[1\] |
|---|---|---|
| \[y\] | \[- 2\] | \[0\] |
