Постройте график функции: y=(x^2+3x-18)/(x-3).

\[x^{2} + 3x - 18 = 0\]

\[x_{1} + x_{2} = - 3;\ \ x_{1} \cdot x_{2} = - 18\]

\[x_{1} = 3,\ \ x_{2} = - 6\]

\[x^{2} + 3x - 18 = (x - 3)(x + 6).\]

\[y = x + 6;\ \ x \neq - 3.\]