Вопрос:

Ответ:

\[y = - \frac{1}{3}x + 1\]

\[x\] \[0\] \[3\]
\[y\] \[1\] \[0\]

\[y = - \frac{1}{3}x - 2\]

\[x\] \[0\] \[3\]
\[y\] \[- 2\] \[- 3\]

\[y = - \frac{1}{3}x\]

\[x\] \[0\] \[3\]
\[y\] \[0\] \[- 1\]

\[k_{1} = k_{2} = k_{3} = - \frac{1}{3}.\]