Ответ:

Приводим дроби к общему знаменателю и сокращаем, где это возможно.

  1. \(\frac{1}{18}+\frac{2}{10}=\frac{5}{90}+\frac{18}{90}=\frac{23}{90}\).
  2. \(\frac{1}{6}-\frac{1}{10}=\frac{5}{30}-\frac{3}{30}=\frac{1}{15}\).
  3. \(\frac{5}{33}+\frac{5}{18}=\frac{30}{198}+\frac{55}{198}=\frac{85}{198}\).
  4. \(\frac{4}{21}-\frac{2}{27}=\frac{36}{189}-\frac{14}{189}=\frac{22}{189}\).
  5. \(\frac{1}{9}+\frac{4}{15}=\frac{5}{45}+\frac{12}{45}=\frac{17}{45}\).
  6. \(\frac{7}{40}-\frac{2}{24}=\frac{21}{120}-\frac{10}{120}=\frac{11}{120}\).
  7. \(\frac{1}{50}+\frac{4}{25}=\frac{1}{50}+\frac{8}{50}=\frac{9}{50}\).
  8. \(\frac{6}{35}-\frac{1}{21}=\frac{18}{105}-\frac{5}{105}=\frac{13}{105}\).
  9. \(\frac{1}{64}+\frac{1}{16}=\frac{1}{64}+\frac{4}{64}=\frac{5}{64}\).
  10. \(\frac{5}{28}-\frac{1}{14}=\frac{5}{28}-\frac{2}{28}=\frac{3}{28}\).
  11. \(\frac{4}{34}+\frac{1}{20}=\frac{2}{17}+\frac{1}{20}=\frac{40}{340}+\frac{17}{340}=\frac{57}{340}\).
  12. \(\frac{8}{44}-\frac{1}{36}=\frac{2}{11}-\frac{1}{36}=\frac{72}{396}-\frac{11}{396}=\frac{61}{396}\).
  13. \(\frac{5}{36}+\frac{1}{45}=\frac{25}{180}+\frac{4}{180}=\frac{29}{180}\).
  14. \(\frac{10}{39}-\frac{3}{24}=\frac{10}{39}-\frac{1}{8}=\frac{80}{312}-\frac{39}{312}=\frac{41}{312}\).