25. Представь числа в виде неправильных дробей. 1= A Б B 2= 3 = 2 = 4- 2 3 = 10 1 14 3 = 2 = 5100- 63 2- 100 9 310 = 13 10 - 7 = 30= 1 12 2 4 = 3 151 100 = = 55 13 3 1윽 = = 50= 2 = 1 3 = = 10 = 1 = 3 = 191 = 100 20 = = 2 4 13 7 = 40= *10 3- 12 9 2 10 = 53 = 14 7 = 4- 10- = 20- = 4 4 = 2- 3 4100 100 111 100 7 3100- 3 - 11 1 8 9 3 = 2- 1 = 5 11 10

A

• \(1\frac{4}{7} = \frac{1 \cdot 7 + 4}{7} = \frac{11}{7}\)
• \(3\frac{1}{10} = \frac{3 \cdot 10 + 1}{10} = \frac{31}{10}\)
• \(1\frac{9}{14} = \frac{1 \cdot 14 + 9}{14} = \frac{23}{14}\)
• \(2\frac{3}{11} = \frac{2 \cdot 11 + 3}{11} = \frac{25}{11}\)
• \(5\frac{7}{100} = \frac{5 \cdot 100 + 7}{100} = \frac{507}{100}\)
• \(2\frac{63}{100} = \frac{2 \cdot 100 + 63}{100} = \frac{263}{100}\)
• \(3\frac{9}{10} = \frac{3 \cdot 10 + 9}{10} = \frac{39}{10}\)
• \(6\frac{1}{6} = \frac{6 \cdot 6 + 1}{6} = \frac{37}{6}\)
• \(1\frac{7}{9} = \frac{1 \cdot 9 + 7}{9} = \frac{16}{9}\)
• \(2\frac{4}{13} = \frac{2 \cdot 13 + 4}{13} = \frac{30}{13}\)
• \(4\frac{7}{10} = \frac{4 \cdot 10 + 7}{10} = \frac{47}{10}\)
• \(3\frac{5}{12} = \frac{3 \cdot 12 + 5}{12} = \frac{41}{12}\)
• \(4\frac{1}{4} = \frac{4 \cdot 4 + 1}{4} = \frac{17}{4}\)
• \(1\frac{11}{100} = \frac{1 \cdot 100 + 11}{100} = \frac{111}{100}\)
• \(3\frac{1}{5} = \frac{3 \cdot 5 + 1}{5} = \frac{16}{5}\)

Б

• \(2\frac{1}{7} = \frac{2 \cdot 7 + 1}{7} = \frac{15}{7}\)
• \(2\frac{3}{13} = \frac{2 \cdot 13 + 3}{13} = \frac{29}{13}\)
• \(1\frac{8}{9} = \frac{1 \cdot 9 + 8}{9} = \frac{17}{9}\)
• \(3\frac{7}{10} = \frac{3 \cdot 10 + 7}{10} = \frac{37}{10}\)
• \(1\frac{11}{12} = \frac{1 \cdot 12 + 11}{12} = \frac{23}{12}\)
• \(2\frac{1}{3} = \frac{2 \cdot 3 + 1}{3} = \frac{7}{3}\)
• \(1\frac{51}{100} = \frac{1 \cdot 100 + 51}{100} = \frac{151}{100}\)
• \(5\frac{1}{10} = \frac{5 \cdot 10 + 1}{10} = \frac{51}{10}\)
• \(3\frac{4}{11} = \frac{3 \cdot 11 + 4}{11} = \frac{37}{11}\)
• \(2\frac{9}{10} = \frac{2 \cdot 10 + 9}{10} = \frac{29}{10}\)
• \(5\frac{3}{14} = \frac{5 \cdot 14 + 3}{14} = \frac{73}{14}\)
• \(4\frac{7}{15} = \frac{4 \cdot 15 + 7}{15} = \frac{67}{15}\)
• \(2\frac{2}{5} = \frac{2 \cdot 5 + 2}{5} = \frac{12}{5}\)
• \(3\frac{9}{100} = \frac{3 \cdot 100 + 9}{100} = \frac{309}{100}\)
• \(2\frac{8}{11} = \frac{2 \cdot 11 + 8}{11} = \frac{30}{11}\)

В

• \(4\frac{1}{2} = \frac{4 \cdot 2 + 1}{2} = \frac{9}{2}\)
• \(3\frac{1}{11} = \frac{3 \cdot 11 + 1}{11} = \frac{34}{11}\)
• \(5\frac{5}{13} = \frac{5 \cdot 13 + 5}{13} = \frac{70}{13}\)
• \(1\frac{3}{7} = \frac{1 \cdot 7 + 3}{7} = \frac{10}{7}\)
• \(5\frac{7}{10} = \frac{5 \cdot 10 + 7}{10} = \frac{57}{10}\)
• \(2\frac{1}{12} = \frac{2 \cdot 12 + 1}{12} = \frac{25}{12}\)
• \(3\frac{5}{9} = \frac{3 \cdot 9 + 5}{9} = \frac{32}{9}\)
• \(1\frac{91}{100} = \frac{1 \cdot 100 + 91}{100} = \frac{191}{100}\)
• \(2\frac{3}{8} = \frac{2 \cdot 8 + 3}{8} = \frac{19}{8}\)
• \(4\frac{1}{10} = \frac{4 \cdot 10 + 1}{10} = \frac{41}{10}\)
• \(1\frac{5}{6} = \frac{1 \cdot 6 + 5}{6} = \frac{11}{6}\)
• \(2\frac{3}{5} = \frac{2 \cdot 5 + 3}{5} = \frac{13}{5}\)
• \(4\frac{3}{100} = \frac{4 \cdot 100 + 3}{100} = \frac{403}{100}\)
• \(3\frac{7}{11} = \frac{3 \cdot 11 + 7}{11} = \frac{40}{11}\)
• \(1\frac{9}{10} = \frac{1 \cdot 10 + 9}{10} = \frac{19}{10}\)