Ответ:
Используем правило: целую часть умножаем на знаменатель и прибавляем числитель дробной части; знаменатель сохраняем.
- \(2\frac{5}{8}=\frac{2\cdot8+5}{8}=\frac{21}{8}\)
- \(5\frac{2}{9}=\frac{5\cdot9+2}{9}=\frac{47}{9}\)
- \(3\frac{4}{5}=\frac{3\cdot5+4}{5}=\frac{19}{5}\)
- \(2\frac{7}{11}=\frac{2\cdot11+7}{11}=\frac{29}{11}\)
- \(5\frac{1}{12}=\frac{5\cdot12+1}{12}=\frac{61}{12}\)
- \(2\frac{4}{9}=\frac{2\cdot9+4}{9}=\frac{22}{9}\)
- \(7\frac{1}{10}=\frac{7\cdot10+1}{10}=\frac{71}{10}\)
- \(4\frac{1}{7}=\frac{4\cdot7+1}{7}=\frac{29}{7}\)
- \(1\frac{3}{8}=\frac{1\cdot8+3}{8}=\frac{11}{8}\)
- \(10\frac{6}{7}=\frac{10\cdot7+6}{7}=\frac{76}{7}\)
- \(9\frac{3}{5}=\frac{9\cdot5+3}{5}=\frac{48}{5}\)
- \(8\frac{3}{4}=\frac{8\cdot4+3}{4}=\frac{35}{4}\)
- \(11\frac{2}{3}=\frac{11\cdot3+2}{3}=\frac{35}{3}\)
- \(10\frac{9}{13}=\frac{10\cdot13+9}{13}=\frac{139}{13}\)
- \(12\frac{1}{2}=\frac{12\cdot2+1}{2}=\frac{25}{2}\)
- \(3\frac{5}{6}=\frac{3\cdot6+5}{6}=\frac{23}{6}\)
- \(7\frac{1}{14}=\frac{7\cdot14+1}{14}=\frac{99}{14}\)
- \(2\frac{16}{17}=\frac{2\cdot17+16}{17}=\frac{50}{17}\)
Ответ: \(\frac{21}{8};\frac{47}{9};\frac{19}{5};\frac{29}{11};\frac{61}{12};\frac{22}{9};\frac{71}{10};\frac{29}{7};\frac{11}{8};\frac{76}{7};\frac{48}{5};\frac{35}{4};\frac{35}{3};\frac{139}{13};\frac{25}{2};\frac{23}{6};\frac{99}{14};\frac{50}{17}\).
