Вопрос:

Представь неправильные дроби в виде смешанных чисел и смешанные числа в виде неправильных дробей 28 = 6 66 13 2 245= 1 213= 23 4 = 71 9 = 5 112= 3 578= 17 = 11 63 11 = 4 5124= 1 57= 43 7 = 47 13 = 2 7315= 2 35= 28 = 4 100 = 24 3 199= 5 18= 57 = 5 69 = 23 6 319= 2 = 36 = 7 37 = 15 7 1229= 3 34= 32 8 = 61 = 14 5 318= 7 68= 119 12 = 41 = 18 1 125= 4 1111= 54 = 43 125 = 25 1 1510= 7 512=

Ответ:

  • $$\frac{28}{6} = 4 \frac{4}{6} = 4 \frac{2}{3}$$
  • $$\frac{66}{13} = 5 \frac{1}{13}$$
  • $$2 \frac{2}{45} = \frac{2 \cdot 45 + 2}{45} = \frac{92}{45}$$
  • $$21 \frac{1}{3} = \frac{21 \cdot 3 + 1}{3} = \frac{64}{3}$$
  • $$\frac{23}{4} = 5 \frac{3}{4}$$
  • $$\frac{71}{9} = 7 \frac{8}{9}$$
  • $$1 \frac{5}{12} = \frac{1 \cdot 12 + 5}{12} = \frac{17}{12}$$
  • $$57 \frac{3}{8} = \frac{57 \cdot 8 + 3}{8} = \frac{459}{8}$$
  • $$\frac{17}{11} = 1 \frac{6}{11}$$
  • $$\frac{63}{11} = 5 \frac{8}{11}$$
  • $$51 \frac{4}{24} = \frac{51 \cdot 24 + 4}{24} = \frac{1228}{24} = \frac{307}{6}$$
  • $$5 \frac{1}{7} = \frac{5 \cdot 7 + 1}{7} = \frac{36}{7}$$
  • $$\frac{43}{7} = 6 \frac{1}{7}$$
  • $$\frac{47}{13} = 3 \frac{8}{13}$$
  • $$73 \frac{2}{15} = \frac{73 \cdot 15 + 2}{15} = \frac{1097}{15}$$
  • $$3 \frac{2}{5} = \frac{3 \cdot 5 + 2}{5} = \frac{17}{5}$$
  • $$\frac{28}{4} = 7$$
  • $$\frac{100}{24} = 4 \frac{4}{24} = 4 \frac{1}{6}$$
  • $$1 \frac{3}{99} = \frac{1 \cdot 99 + 3}{99} = \frac{102}{99} = \frac{34}{33}$$
  • $$1 \frac{5}{8} = \frac{1 \cdot 8 + 5}{8} = \frac{13}{8}$$
  • $$\frac{57}{5} = 11 \frac{2}{5}$$
  • $$\frac{69}{23} = 3$$
  • $$3 \frac{6}{19} = \frac{3 \cdot 19 + 6}{19} = \frac{63}{19}$$
  • $$2 = \frac{2}{1}$$
  • $$\frac{36}{7} = 5 \frac{1}{7}$$
  • $$\frac{37}{15} = 2 \frac{7}{15}$$
  • $$12 \frac{7}{29} = \frac{12 \cdot 29 + 7}{29} = \frac{355}{29}$$
  • $$3 \frac{3}{4} = \frac{3 \cdot 4 + 3}{4} = \frac{15}{4}$$
  • $$\frac{32}{8} = 4$$
  • $$\frac{61}{14} = 4 \frac{5}{14}$$
  • $$3 \frac{5}{18} = \frac{3 \cdot 18 + 5}{18} = \frac{59}{18}$$
  • $$6 \frac{7}{8} = \frac{6 \cdot 8 + 7}{8} = \frac{55}{8}$$
  • $$\frac{119}{12} = 9 \frac{11}{12}$$
  • $$\frac{41}{18} = 2 \frac{5}{18}$$
  • $$12 \frac{1}{5} = \frac{12 \cdot 5 + 1}{5} = \frac{61}{5}$$
  • $$11 \frac{4}{11} = \frac{11 \cdot 11 + 4}{11} = \frac{125}{11}$$
  • $$\frac{54}{43} = 1 \frac{11}{43}$$
  • $$\frac{125}{25} = 5$$
  • $$15 \frac{1}{10} = \frac{15 \cdot 10 + 1}{10} = \frac{151}{10}$$
  • $$5 \frac{7}{12} = \frac{5 \cdot 12 + 7}{12} = \frac{67}{12}$$

Ответ: См.выше

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