Преобразуем неправильные дроби в смешанные числа и смешанные числа в неправильные дроби:
- $$ \frac{28}{6} = 4\frac{4}{6} = 4\frac{2}{3} $$
- $$ \frac{66}{13} = 5\frac{1}{13} $$
- $$ 2\frac{2}{45} = \frac{2 \cdot 45 + 2}{45} = \frac{90 + 2}{45} = \frac{92}{45} $$
- $$ 21\frac{1}{3} = \frac{21 \cdot 3 + 1}{3} = \frac{63 + 1}{3} = \frac{64}{3} $$
- $$ \frac{23}{4} = 5\frac{3}{4} $$
- $$ \frac{71}{9} = 7\frac{8}{9} $$
- $$ 1\frac{5}{12} = \frac{1 \cdot 12 + 5}{12} = \frac{12 + 5}{12} = \frac{17}{12} $$
- $$ 57\frac{3}{8} = \frac{57 \cdot 8 + 3}{8} = \frac{456 + 3}{8} = \frac{459}{8} $$
- $$ \frac{17}{11} = 1\frac{6}{11} $$
- $$ \frac{63}{11} = 5\frac{8}{11} $$
- $$ 51\frac{4}{24} = \frac{51 \cdot 24 + 4}{24} = \frac{1224 + 4}{24} = \frac{1228}{24} = \frac{307}{6} $$
- $$ 5\frac{1}{7} = \frac{5 \cdot 7 + 1}{7} = \frac{35 + 1}{7} = \frac{36}{7} $$
- $$ \frac{43}{7} = 6\frac{1}{7} $$
- $$ \frac{47}{13} = 3\frac{8}{13} $$
- $$ 73\frac{2}{15} = \frac{73 \cdot 15 + 2}{15} = \frac{1095 + 2}{15} = \frac{1097}{15} $$
- $$ 3\frac{2}{5} = \frac{3 \cdot 5 + 2}{5} = \frac{15 + 2}{5} = \frac{17}{5} $$
- $$ \frac{28}{4} = 7 $$
- $$ \frac{100}{24} = 4\frac{4}{24} = 4\frac{1}{6} $$
- $$ 1\frac{3}{99} = \frac{1 \cdot 99 + 3}{99} = \frac{99 + 3}{99} = \frac{102}{99} = \frac{34}{33} $$
- $$ 1\frac{5}{8} = \frac{1 \cdot 8 + 5}{8} = \frac{8 + 5}{8} = \frac{13}{8} $$
- $$ \frac{57}{5} = 11\frac{2}{5} $$
- $$ \frac{69}{23} = 3 $$
- $$ 3\frac{6}{19} = \frac{3 \cdot 19 + 6}{19} = \frac{57 + 6}{19} = \frac{63}{19} $$
- $$ 2 = \frac{2}{1} $$
- $$ \frac{36}{7} = 5\frac{1}{7} $$
- $$ \frac{37}{15} = 2\frac{7}{15} $$
- $$ 12\frac{7}{29} = \frac{12 \cdot 29 + 7}{29} = \frac{348 + 7}{29} = \frac{355}{29} $$
- $$ 3\frac{3}{4} = \frac{3 \cdot 4 + 3}{4} = \frac{12 + 3}{4} = \frac{15}{4} $$
- $$ \frac{32}{8} = 4 $$
- $$ \frac{61}{14} = 4\frac{5}{14} $$
- $$ 3\frac{5}{18} = \frac{3 \cdot 18 + 5}{18} = \frac{54 + 5}{18} = \frac{59}{18} $$
- $$ 6\frac{7}{8} = \frac{6 \cdot 8 + 7}{8} = \frac{48 + 7}{8} = \frac{55}{8} $$
- $$ \frac{119}{12} = 9\frac{11}{12} $$
- $$ \frac{41}{18} = 2\frac{5}{18} $$
- $$ 12\frac{1}{5} = \frac{12 \cdot 5 + 1}{5} = \frac{60 + 1}{5} = \frac{61}{5} $$
- $$ 11\frac{4}{11} = \frac{11 \cdot 11 + 4}{11} = \frac{121 + 4}{11} = \frac{125}{11} $$
- $$ \frac{54}{43} = 1\frac{11}{43} $$
- $$ \frac{125}{25} = 5 $$
- $$ 15\frac{1}{10} = \frac{15 \cdot 10 + 1}{10} = \frac{150 + 1}{10} = \frac{151}{10} $$
- $$ 5\frac{7}{12} = \frac{5 \cdot 12 + 7}{12} = \frac{60 + 7}{12} = \frac{67}{12} $$
Ответ: См. решение.