Представь в виде неправильной дроби число. Б

Решение:

1. $$1 \frac{2}{99} = \frac{1 \cdot 99 + 2}{99} = \frac{99 + 2}{99} = \frac{101}{99}$$
2. $$15 \frac{1}{10} = \frac{15 \cdot 10 + 1}{10} = \frac{150 + 1}{10} = \frac{151}{10}$$
3. $$3 \frac{10}{19} = \frac{3 \cdot 19 + 10}{19} = \frac{57 + 10}{19} = \frac{67}{19}$$
4. $$1 \frac{2}{121} = \frac{1 \cdot 121 + 2}{121} = \frac{121 + 2}{121} = \frac{123}{121}$$
5. $$5 \frac{5}{6} = \frac{5 \cdot 6 + 5}{6} = \frac{30 + 5}{6} = \frac{35}{6}$$
6. $$7 \frac{15}{100} = \frac{7 \cdot 100 + 15}{100} = \frac{700 + 15}{100} = \frac{715}{100}$$
7. $$16,2 = 16 \frac{2}{10} = \frac{16 \cdot 10 + 2}{10} = \frac{160 + 2}{10} = \frac{162}{10}$$
8. $$14 = \frac{14}{1}$$
9. $$11 \frac{2}{99} = \frac{11 \cdot 99 + 2}{99} = \frac{1089 + 2}{99} = \frac{1091}{99}$$
10. $$6 \frac{5}{32} = \frac{6 \cdot 32 + 5}{32} = \frac{192 + 5}{32} = \frac{197}{32}$$
11. $$1 \frac{2}{3} = \frac{1 \cdot 3 + 2}{3} = \frac{3 + 2}{3} = \frac{5}{3}$$
12. $$10,5 = 10 \frac{5}{10} = \frac{10 \cdot 10 + 5}{10} = \frac{100 + 5}{10} = \frac{105}{10}$$
13. $$19 \frac{1}{2} = \frac{19 \cdot 2 + 1}{2} = \frac{38 + 1}{2} = \frac{39}{2}$$
14. $$18 \frac{1}{5} = \frac{18 \cdot 5 + 1}{5} = \frac{90 + 1}{5} = \frac{91}{5}$$
15. $$10 = \frac{10}{1}$$

Ответ:

• $$\frac{101}{99}$$
• $$\frac{151}{10}$$
• $$\frac{67}{19}$$
• $$\frac{123}{121}$$
• $$\frac{35}{6}$$
• $$\frac{715}{100}$$
• $$\frac{162}{10}$$
• $$\frac{14}{1}$$
• $$\frac{1091}{99}$$
• $$\frac{197}{32}$$
• $$\frac{5}{3}$$
• $$\frac{105}{10}$$
• $$\frac{39}{2}$$
• $$\frac{91}{5}$$
• $$\frac{10}{1}$$