2. Представьте смешанное число в виде суммы, а затем в виде неправильной дроби: 1) 3 4/11 = 2) 4 5/6 = 3) 3 7/18 = 4) 11 2/3 = 5) 5 11/12 = 6) 8 3/9 =

1) $$3 \frac{4}{11} = 3 + \frac{4}{11} = \frac{3 \cdot 11 + 4}{11} = \frac{33+4}{11} = \frac{37}{11}$$

2) $$4 \frac{5}{6} = 4 + \frac{5}{6} = \frac{4 \cdot 6 + 5}{6} = \frac{24+5}{6} = \frac{29}{6}$$

3) $$3 \frac{7}{18} = 3 + \frac{7}{18} = \frac{3 \cdot 18 + 7}{18} = \frac{54+7}{18} = \frac{61}{18}$$

4) $$11 \frac{2}{3} = 11 + \frac{2}{3} = \frac{11 \cdot 3 + 2}{3} = \frac{33+2}{3} = \frac{35}{3}$$

5) $$5 \frac{11}{12} = 5 + \frac{11}{12} = \frac{5 \cdot 12 + 11}{12} = \frac{60+11}{12} = \frac{71}{12}$$

6) $$8 \frac{3}{9} = 8 + \frac{3}{9} = \frac{8 \cdot 9 + 3}{9} = \frac{72+3}{9} = \frac{75}{9}$$

Ответ: 37/11; 29/6; 61/18; 35/3; 71/12; 75/9