Решение задания 253

1. a) $$16x^8 = (4x^4)^2$$
2. б) $$\frac{1}{81}a^4b^2 = (\frac{1}{9}a^2b)^2$$
3. в) $$0.01x^8y^{16} = (0.1x^4y^8)^2$$
4. г) $$1.21a^4b^6c^2 = (1.1a^2b^3c)^2$$