Используем правило: \(a\frac{b}{c}=\frac{ac+b}{c}\).
- \(4\frac{5}{8}=\frac{4\cdot8+5}{8}=\frac{37}{8}\)
- \(1\frac{19}{25}=\frac{1\cdot25+19}{25}=\frac{44}{25}\)
- \(3\frac{4}{9}=\frac{31}{9}\)
- \(5\frac{1}{3}=\frac{16}{3}\)
- \(6\frac{2}{5}=\frac{32}{5}\)
- \(2\frac{6}{13}=\frac{32}{13}\)
- \(7\frac{1}{5}=\frac{36}{5}\)
- \(5\frac{5}{11}=\frac{60}{11}\)
- \(6\frac{2}{7}=\frac{44}{7}\)
- \(3\frac{1}{9}=\frac{28}{9}\)
- \(29\frac{1}{2}=\frac{59}{2}\)
- \(7\frac{5}{8}=\frac{61}{8}\)
- \(9\frac{3}{4}=\frac{39}{4}\)
- \(11\frac{3}{5}=\frac{58}{5}\)
- \(13\frac{1}{2}=\frac{27}{2}\)
- \(7\frac{4}{5}=\frac{39}{5}\)
- \(3\frac{5}{6}=\frac{23}{6}\)
- \(13\frac{4}{9}=\frac{121}{9}\)
- \(5\frac{7}{8}=\frac{47}{8}\)
- \(4\frac{5}{7}=\frac{33}{7}\)
Ответ: \(\frac{37}{8};\frac{44}{25};\frac{31}{9};\frac{16}{3};\frac{32}{5};\frac{32}{13};\frac{36}{5};\frac{60}{11};\frac{44}{7};\frac{28}{9};\frac{59}{2};\frac{61}{8};\frac{39}{4};\frac{58}{5};\frac{27}{2};\frac{39}{5};\frac{23}{6};\frac{121}{9};\frac{47}{8};\frac{33}{7}\).