Ответ: Решение приведения дробей к общему знаменателю в таблице ниже.
| № | Исходные дроби | Общий знаменатель | Преобразованные дроби |
|---|---|---|---|
| 1 | \[\frac{7}{13}\] и \[\frac{11}{12}\] | 156 | \[\frac{7 \cdot 12}{156} = \frac{84}{156}\] и \[\frac{11 \cdot 13}{156} = \frac{143}{156}\] |
| 2 | \[\frac{10}{16}\] и \[\frac{11}{14}\] | 112 | \[\frac{10 \cdot 7}{112} = \frac{70}{112}\] и \[\frac{11 \cdot 8}{112} = \frac{88}{112}\] |
| 3 | \[\frac{16}{2}\] и \[\frac{13}{3}\] | 6 | \[\frac{16 \cdot 3}{6} = \frac{48}{6}\] и \[\frac{13 \cdot 2}{6} = \frac{26}{6}\] |
| 4 | \[\frac{2}{11}\] и \[\frac{3}{5}\] | 55 | \[\frac{2 \cdot 5}{55} = \frac{10}{55}\] и \[\frac{3 \cdot 11}{55} = \frac{33}{55}\] |
| 5 | \[\frac{11}{3}\] и \[\frac{5}{10}\] | 30 | \[\frac{11 \cdot 10}{30} = \frac{110}{30}\] и \[\frac{5 \cdot 3}{30} = \frac{15}{30}\] |
| 6 | \[\frac{4}{13}\] и \[\frac{11}{6}\] | 78 | \[\frac{4 \cdot 6}{78} = \frac{24}{78}\] и \[\frac{11 \cdot 13}{78} = \frac{143}{78}\] |
| 7 | \[\frac{13}{10}\] и \[\frac{6}{2}\] | 10 | \[\frac{13 \cdot 1}{10} = \frac{13}{10}\] и \[\frac{6 \cdot 5}{10} = \frac{30}{10}\] |
| 8 | \[\frac{10}{14}\] и \[\frac{2}{9}\] | 63 | \[\frac{10 \cdot 9}{126} = \frac{90}{126}\] и \[ \frac{2 \cdot 14}{126} = \frac{28}{126}\] |
| 9 | \[\frac{10}{16}\] и \[ \frac{9}{15}\] | 240 | \[\frac{10 \cdot 15}{240} = \frac{150}{240}\] и \[ \frac{9 \cdot 16}{240} = \frac{144}{240}\] |
| 10 | \[\frac{12}{14}\] и \[ \frac{13}{12}\] | 84 | \[\frac{12 \cdot 6}{84} = \frac{72}{84}\] и \[ \frac{13 \cdot 7}{84} = \frac{91}{84}\] |
| 11 | \[\frac{16}{12}\] и \[ \frac{13}{15}\] | 60 | \[\frac{16 \cdot 5}{60} = \frac{80}{60}\] и \[ \frac{13 \cdot 4}{60} = \frac{52}{60}\] |
| 12 | \[\frac{12}{15}\] и \[ \frac{15}{2}\] | 30 | \[\frac{12 \cdot 2}{30} = \frac{24}{30}\] и \[ \frac{15 \cdot 15}{30} = \frac{225}{30}\] |
| 13 | \[\frac{15}{6}\] и \[ \frac{2}{13}\] | 78 | \[\frac{15 \cdot 13}{78} = \frac{195}{78}\] и \[ \frac{2 \cdot 6}{78} = \frac{12}{78}\] |
| 14 | \[\frac{6}{16}\] и \[ \frac{13}{15}\] | 240 | \[\frac{6 \cdot 15}{240} = \frac{90}{240}\] и \[ \frac{13 \cdot 16}{240} = \frac{208}{240}\] |
| 15 | \[\frac{8}{14}\] и \[ \frac{7}{9}\] | 63 | \[\frac{8 \cdot 9}{63} = \frac{72}{63}\] и \[ \frac{7 \cdot 7}{63} = \frac{49}{63}\] |
| 16 | \[\frac{14}{11}\] и \[ \frac{9}{6}\] | 66 | \[\frac{14 \cdot 6}{66} = \frac{84}{66}\] и \[ \frac{9 \cdot 11}{66} = \frac{99}{66}\] |
| 17 | \[\frac{11}{16}\] и \[ \frac{6}{11}\] | 176 | \[\frac{11 \cdot 11}{176} = \frac{121}{176}\] и \[ \frac{6 \cdot 16}{176} = \frac{96}{176}\] |
Ответ: Решение приведения дробей к общему знаменателю в таблице выше.
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