Ответ:

  1. \((10-\frac{1}{3})\cdot3=10\cdot3-\frac{1}{3}\cdot3=30-1=\mathbf{29}\).
  2. \((\frac{1}{5}+\frac{1}{3})\cdot15=\frac{1}{5}\cdot15+\frac{1}{3}\cdot15=3+5=\mathbf{8}\).
  3. \((\frac{7}{8}-\frac{1}{6})\cdot24=\frac{7}{8}\cdot24-\frac{1}{6}\cdot24=21-4=\mathbf{17}\).
  4. \((3+9)\cdot\frac{1}{3}=3\cdot\frac{1}{3}+9\cdot\frac{1}{3}=1+3=\mathbf{4}\).
  5. \((7-\frac{3}{4})\cdot\frac{1}{3}=7\cdot\frac{1}{3}-\frac{3}{4}\cdot\frac{1}{3}=\frac{7}{3}-\frac{1}{4}=\frac{28}{12}-\frac{3}{12}=\mathbf{\frac{25}{12}}\).
  6. \((\frac{1}{7}+2)\cdot\frac{7}{9}=\frac{1}{7}\cdot\frac{7}{9}+2\cdot\frac{7}{9}=\frac{1}{9}+\frac{14}{9}=\mathbf{\frac{5}{3}}\).