Привет! Сейчас помогу тебе разобраться с этими примерами на сложение дробей. Будем решать их пошагово, чтобы тебе было всё понятно.
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\[\frac{14}{27} + \frac{2}{27} = \frac{14+2}{27} = \frac{16}{27}\]
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\[\frac{11}{35} + \frac{12}{35} = \frac{11+12}{35} = \frac{23}{35}\]
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\[\frac{17}{60} + \frac{12}{60} = \frac{17+12}{60} = \frac{29}{60}\]
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\[\frac{32}{55} + \frac{23}{55} = \frac{32+23}{55} = \frac{55}{55} = 1\]
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\[\frac{5}{33} + \frac{6}{33} = \frac{5+6}{33} = \frac{11}{33} = \frac{1}{3}\]
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\[\frac{12}{48} + \frac{12}{48} = \frac{12+12}{48} = \frac{24}{48} = \frac{1}{2}\]
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\[\frac{1}{2} + \frac{1}{3} = \frac{1 \cdot 3}{2 \cdot 3} + \frac{1 \cdot 2}{3 \cdot 2} = \frac{3}{6} + \frac{2}{6} = \frac{3+2}{6} = \frac{5}{6}\]
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\[\frac{1}{3} + \frac{1}{4} = \frac{1 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3} = \frac{4}{12} + \frac{3}{12} = \frac{4+3}{12} = \frac{7}{12}\]
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\[\frac{1}{3} + \frac{1}{6} = \frac{1 \cdot 2}{3 \cdot 2} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{2+1}{6} = \frac{3}{6} = \frac{1}{2}\]
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\[\frac{1}{10} + \frac{7}{100} = \frac{1 \cdot 10}{10 \cdot 10} + \frac{7}{100} = \frac{10}{100} + \frac{7}{100} = \frac{10+7}{100} = \frac{17}{100}\]
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\[\frac{3}{5} + \frac{9}{10} = \frac{3 \cdot 2}{5 \cdot 2} + \frac{9}{10} = \frac{6}{10} + \frac{9}{10} = \frac{6+9}{10} = \frac{15}{10} = \frac{3}{2} = 1\frac{1}{2}\]
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\[\frac{2}{3} + \frac{5}{6} = \frac{2 \cdot 2}{3 \cdot 2} + \frac{5}{6} = \frac{4}{6} + \frac{5}{6} = \frac{4+5}{6} = \frac{9}{6} = \frac{3}{2} = 1\frac{1}{2}\]
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\[\frac{15}{24} + \frac{3}{8} = \frac{15}{24} + \frac{3 \cdot 3}{8 \cdot 3} = \frac{15}{24} + \frac{9}{24} = \frac{15+9}{24} = \frac{24}{24} = 1\]
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\[\frac{1}{2} + \frac{3}{10} = \frac{1 \cdot 5}{2 \cdot 5} + \frac{3}{10} = \frac{5}{10} + \frac{3}{10} = \frac{5+3}{10} = \frac{8}{10} = \frac{4}{5}\]
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\[\frac{3}{36} + \frac{7}{9} = \frac{3}{36} + \frac{7 \cdot 4}{9 \cdot 4} = \frac{3}{36} + \frac{28}{36} = \frac{3+28}{36} = \frac{31}{36}\]
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\[\frac{2}{5} + \frac{3}{20} = \frac{2 \cdot 4}{5 \cdot 4} + \frac{3}{20} = \frac{8}{20} + \frac{3}{20} = \frac{8+3}{20} = \frac{11}{20}\]
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\[\frac{1}{6} + \frac{5}{12} = \frac{1 \cdot 2}{6 \cdot 2} + \frac{5}{12} = \frac{2}{12} + \frac{5}{12} = \frac{2+5}{12} = \frac{7}{12}\]
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\[\frac{11}{49} + \frac{6}{7} = \frac{11}{49} + \frac{6 \cdot 7}{7 \cdot 7} = \frac{11}{49} + \frac{42}{49} = \frac{11+42}{49} = \frac{53}{49} = 1\frac{4}{49}\]
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\[\frac{13}{24} + \frac{5}{8} = \frac{13}{24} + \frac{5 \cdot 3}{8 \cdot 3} = \frac{13}{24} + \frac{15}{24} = \frac{13+15}{24} = \frac{28}{24} = \frac{7}{6} = 1\frac{1}{6}\]
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\[\frac{3}{8} + \frac{6}{32} = \frac{3 \cdot 4}{8 \cdot 4} + \frac{6}{32} = \frac{12}{32} + \frac{6}{32} = \frac{12+6}{32} = \frac{18}{32} = \frac{9}{16}\]
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\[\frac{6}{120} + \frac{3}{20} = \frac{6}{120} + \frac{3 \cdot 6}{20 \cdot 6} = \frac{6}{120} + \frac{18}{120} = \frac{6+18}{120} = \frac{24}{120} = \frac{1}{5}\]
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\[\frac{9}{16} + \frac{50}{100} = \frac{9 \cdot 25}{16 \cdot 25} + \frac{50 \cdot 4}{100 \cdot 4} = \frac{225}{400} + \frac{200}{400} = \frac{225+200}{400} = \frac{425}{400} = \frac{17}{16} = 1\frac{1}{16}\]
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\[\frac{1}{6} + \frac{1}{9} = \frac{1 \cdot 3}{6 \cdot 3} + \frac{1 \cdot 2}{9 \cdot 2} = \frac{3}{18} + \frac{2}{18} = \frac{3+2}{18} = \frac{5}{18}\]
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\[\frac{2}{9} + \frac{5}{6} = \frac{2 \cdot 2}{9 \cdot 2} + \frac{5 \cdot 3}{6 \cdot 3} = \frac{4}{18} + \frac{15}{18} = \frac{4+15}{18} = \frac{19}{18} = 1\frac{1}{18}\]
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\[\frac{2}{9} + \frac{3}{8} = \frac{2 \cdot 8}{9 \cdot 8} + \frac{3 \cdot 9}{8 \cdot 9} = \frac{16}{72} + \frac{27}{72} = \frac{16+27}{72} = \frac{43}{72}\]
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\[\frac{2}{10} + \frac{6}{15} = \frac{2 \cdot 3}{10 \cdot 3} + \frac{6 \cdot 2}{15 \cdot 2} = \frac{6}{30} + \frac{12}{30} = \frac{6+12}{30} = \frac{18}{30} = \frac{3}{5}\]
Ответ: Решения выше.
Ты отлично справляешься! Продолжай в том же духе, и у тебя всё получится!