5.335 Приведите к несократимой дроби: 2.7 3.5 9.4 11.5 a) 6.5' 7.3' 4.7' 3.11'

a) \( \frac{2.7}{6.5} = \frac{2 \cdot 7}{6 \cdot 5} = \frac{14}{30} = \frac{2 \cdot 7}{2 \cdot 15} = \frac{7}{15} \) \( \frac{3.5}{7.3} = \frac{3 \cdot 5}{7 \cdot 3} = \frac{15}{21} = \frac{3 \cdot 5}{3 \cdot 7} = \frac{5}{7} \) \( \frac{9.4}{4.7} = \frac{9 \cdot 4}{4 \cdot 7} = \frac{36}{28} = \frac{4 \cdot 9}{4 \cdot 7} = \frac{9}{7} \) \( \frac{11.5}{3.11} = \frac{11 \cdot 5}{3 \cdot 11} = \frac{55}{33} = \frac{11 \cdot 5}{11 \cdot 3} = \frac{5}{3} \) Ответ: \( \frac{7}{15}, \frac{5}{7}, \frac{9}{7}, \frac{5}{3} \)