Ответ:
\[2x^{2} + 5x + 2 = 0\]
\[D = 25 - 16 = 9\]
\[x_{1} = \frac{- 5 + 3}{4} = - \frac{2}{4} = - \frac{1}{2};\]
\[x_{2} = \frac{- 5 - 3}{4} = - 2;\]
\[2x^{2} + 5x + 2 = 2(x + 2)\left( x + \frac{1}{2} \right) =\]
\[= (2x + 1)(x + 2).\]
\[2x^{2} + 5x + 2 = 0\]
\[D = 25 - 16 = 9\]
\[x_{1} = \frac{- 5 + 3}{4} = - \frac{2}{4} = - \frac{1}{2};\]
\[x_{2} = \frac{- 5 - 3}{4} = - 2;\]
\[2x^{2} + 5x + 2 = 2(x + 2)\left( x + \frac{1}{2} \right) =\]
\[= (2x + 1)(x + 2).\]