Решим уравнение:
$$54z^2 + 2 = (3z + 1)(18z + 3)$$ $$54z^2 + 2 = 54z^2 + 9z + 18z + 3$$ $$54z^2 + 2 = 54z^2 + 27z + 3$$ $$54z^2 - 54z^2 - 27z = 3 - 2$$ $$-27z = 1$$ $$z = -\frac{1}{27}$$
Ответ:
$$\mathbf{-}\frac{\mathbf{1}}{\mathbf{27}}$$
Ответ: $$\mathbf{-}\frac{\mathbf{1}}{\mathbf{27}}$$