Ответ:

  1. \(x=4\frac{2}{7}-1\frac{4}{9}=\frac{30}{7}-\frac{13}{9}=\frac{270-91}{63}=\frac{179}{63}=2\frac{53}{63}\).
  2. \(x+\frac{4}{7}=\frac{1}{4}+\frac{9}{14}=\frac{7}{28}+\frac{18}{28}=\frac{25}{28}\), поэтому \(x=\frac{25}{28}-\frac{4}{7}=\frac{25}{28}-\frac{16}{28}=\frac{9}{28}\).
  3. \(x=5\frac{4}{9}-2\frac{3}{5}=\frac{49}{9}-\frac{13}{5}=\frac{245-117}{45}=\frac{128}{45}=2\frac{38}{45}\).
  4. \(x+\frac{5}{12}=\frac{1}{3}+\frac{7}{18}=\frac{6}{18}+\frac{7}{18}=\frac{13}{18}\), поэтому \(x=\frac{13}{18}-\frac{5}{12}=\frac{26-15}{36}=\frac{11}{36}\).

Ответ: 1) \(2\frac{53}{63}\); 2) \(\frac{9}{28}\); 3) \(2\frac{38}{45}\); 4) \(\frac{11}{36}\).