1) \(\frac{2000}{x}=40\)
\(x = \frac{2000}{40}\)
\(x = 50\) (Д)
2) \(\frac{y}{70}=5\)
\(y= 5 \cdot 70\)
\(y = 350\) (Е)
3) (60 \(\cdot\) a – 32) : 16 = 13
(60 \(\cdot\) a - 32) = 13 \(\cdot\) 16
60 \(\cdot\) a = 208 + 32
60 \(\cdot\) a = 240
a = 240 : 60
a = 4 (К)
4) 75 – 960 : (b + 39) = 55
960 : (b + 39) = 75 - 55
960 : (b + 39) = 20
b + 39 = 960 : 20
b + 39 = 48
b = 48 - 39
b = 9 (М)
5) \(12\frac{7}{23} - (6\frac{18}{23} - t) = 3\frac{21}{23} + 5\frac{19}{23}\)
\(12\frac{7}{23} - (6\frac{18}{23} - t) = 8\frac{40}{23}\)
\(12\frac{7}{23} - (6\frac{18}{23} - t) = 9\frac{17}{23}\)
\(6\frac{18}{23} - t = 12\frac{7}{23} - 9\frac{17}{23}\)
\(6\frac{18}{23} - t = 2\frac{13}{23}\)
\(t = 6\frac{18}{23} - 2\frac{13}{23}\)
\(t = 4\frac{5}{23}\) (О)
6) \((k - 5\frac{3}{14}) + 8\frac{13}{14} = 15 - 3\frac{9}{14}\)
\((k - 5\frac{3}{14}) + 8\frac{13}{14} = 14\frac{14}{14} - 3\frac{9}{14}\)
\((k - 5\frac{3}{14}) + 8\frac{13}{14} = 11\frac{5}{14}\)
\(k - 5\frac{3}{14} = 11\frac{5}{14} - 8\frac{13}{14}\)
\(k - 5\frac{3}{14} = 10\frac{19}{14} - 8\frac{13}{14}\)
\(k - 5\frac{3}{14} = 2\frac{6}{14}\)
\(k = 2\frac{6}{14} + 5\frac{3}{14}\)
\(k = 7\frac{9}{14}\) (Н)
Вставим буквы в "окошки": Д, Е, К, М, О, Н. Имя: Демокн.
Ответ: Демокн.