$$8x(1+2x)-(4x+3)(4x-3) = 2x$$
$$8x + 16x^2 - (16x^2 - 9) = 2x$$
$$8x + 16x^2 - 16x^2 + 9 = 2x$$
$$8x + 9 = 2x$$
$$6x = -9$$
$$x = \frac{-9}{6} = -\frac{3}{2} = -1.5$$
Ответ: $$x = -1.5$$