Решите неравенство: 2 2/3 x>9/16.

\[2\frac{2}{3}x > \frac{9}{16}\]

\[x > \frac{9 \cdot 3}{16 \cdot 8}\]

\[x > \frac{27}{128}\]

\[Ответ:\left( \frac{27}{128};\ + \infty \right).\]