Ответ:
\[\frac{2x + 1}{x - 3} \leq 1^{\backslash x - 3}\]
\[\frac{2x + 1 - x + 3}{x - 3} \leq 0\]
\[\frac{x + 4}{x - 3} \leq 0;\ \ \ \ x \neq 3\]

\[- 4 \leq x < 3.\]
\[Ответ:2.\]
\[\frac{2x + 1}{x - 3} \leq 1^{\backslash x - 3}\]
\[\frac{2x + 1 - x + 3}{x - 3} \leq 0\]
\[\frac{x + 4}{x - 3} \leq 0;\ \ \ \ x \neq 3\]

\[- 4 \leq x < 3.\]
\[Ответ:2.\]