Решите неравенство: (3x+1)/(x-2)<1.

\[\frac{3x + 1}{x - 2} < 1\]

\[\frac{3x + 1}{x - 2} - 1^{\backslash x - 2} < 0\]

\[\frac{3x + 1 - x + 2}{x - 2} < 0\]

\[\frac{2x + 3}{x - 2} < 0\]

\[\frac{2 \cdot (x + 1,5)}{x - 2} < 0\]

\[Ответ:( - 1,5;2).\]