Решите неравенство: 3x^2+18x>=0.

\[3x² + 18x \geq 0\]

\[3x(x + 6) \geq 0\]

\[x = 0,\ \ x = - 6\]

\[Ответ:( - \infty;\ - 6\rbrack \cup \lbrack 0;\ + \infty).\]