Решите неравенство: (3x-1)/(x+3)>0.

\[\frac{3x - 1}{x + 3} > 0\]

\[\frac{3 \cdot \left( x - \frac{1}{3} \right)}{x - ( - 3)} > 0\]

\[Ответ:( - \infty; - 3) \cup \left( \frac{1}{3}; + \infty \right)\text{.\ }\]