Решите неравенство: 4x+7<=6x+1.

\[4x + 7 \leq 6x + 1\]

\[4x - 6x \leq 1 - 7\]

\[- 2x \leq - 6\]

\[x \geq 3\]

\[Ответ:x \in \lbrack 3; + \infty).\]