Решите неравенство: 4x^2-16x<=0.

\[4x^{2} - 16x \leq 0\]

\[4x(x - 4) \leq 0\]

\[4x(x - 4) = 0\]

\[x = 0,\ \ \ x = 4\]

\[Ответ:x \in \lbrack 0;4\rbrack.\]