Решите неравенство: (x^2+8x+18)/(5x-3)<0.

\[\frac{x^{2} + 8x + 18}{5x - 3} < 0\]

\[\frac{(x + 4)^{2} + 2}{5x - 3} < 0\]

\[(x + 4)^{2} + 2 > 0\ \ \]

\[при\ любом\ x \in R;\]

\[5x - 3 < 0 \Longrightarrow x < 0,6\]

\[Ответ:( - \infty;0,6).\]