Решите неравенство: (x^2-x-2)/(x-2)>0.

Question

\[\frac{x^{2} - x - 2}{x - 2} > 0\]

\[\frac{(x - 2)(x + 1)}{x - 2} > 0\]

\[Ответ:( - 1;2) \cup (2; + \infty).\]

Accepted Answer

\[\frac{x^{2} - x - 2}{x - 2} > 0\]

\[\frac{(x - 2)(x + 1)}{x - 2} > 0\]

\[Ответ:( - 1;2) \cup (2; + \infty).\]