Решите неравенство: ((x-1)(x^2-49))/(x^2+8)<=0.

\[\frac{(x - 1)\left( x^{2} - 49 \right)}{x^{2} + 8} \leq 0\]

\[Так\ как\ x^{2} + 8 > 0\ при\ \]

\[любом\ x:\]

\[(x - 1)\left( x^{2} - 49 \right) \leq 0\]

\[(x + 7)(x - 1)(x - 7) \leq 0\]

\[x \leq - 7;\ \ 1 \leq x \leq 7.\]