467. Решите примеры. 11\frac{3}{8}-4\frac{7}{8} 15\frac{1}{5}-6\frac{4}{5} 9\frac{7}{10}+3\frac{9}{10}-4 13\frac{4}{9}-2\frac{5}{9} 8\frac{5}{6}+3\frac{5}{6}-7 8-3\frac{4}{15}+6\frac{7}{15}

Решим примеры:

1. $$11\frac{3}{8}-4\frac{7}{8} = 10\frac{11}{8}-4\frac{7}{8} = (10-4)+\frac{11-7}{8} = 6+\frac{4}{8} = 6\frac{1}{2}$$
2. $$15\frac{1}{5}-6\frac{4}{5} = 14\frac{6}{5}-6\frac{4}{5} = (14-6)+\frac{6-4}{5} = 8+\frac{2}{5} = 8\frac{2}{5}$$
3. $$9\frac{7}{10}+3\frac{9}{10}-4 = (9+3-4)+\frac{7+9}{10} = 8+\frac{16}{10} = 8+1\frac{6}{10} = 9\frac{3}{5}$$
4. $$13\frac{4}{9}-2\frac{5}{9} = 12\frac{13}{9}-2\frac{5}{9} = (12-2)+\frac{13-5}{9} = 10+\frac{8}{9} = 10\frac{8}{9}$$
5. $$8\frac{5}{6}+3\frac{5}{6}-7 = (8+3-7)+\frac{5+5}{6} = 4+\frac{10}{6} = 4+1\frac{4}{6} = 5\frac{2}{3}$$
6. $$8-3\frac{4}{15}+6\frac{7}{15} = (8-3+6)+\frac{-4+7}{15} = 11+\frac{3}{15} = 11+\frac{1}{5} = 11\frac{1}{5}$$

Ответ:

1. $$11\frac{3}{8}-4\frac{7}{8} = 6\frac{1}{2}$$
2. $$15\frac{1}{5}-6\frac{4}{5} = 8\frac{2}{5}$$
3. $$9\frac{7}{10}+3\frac{9}{10}-4 = 9\frac{3}{5}$$
4. $$13\frac{4}{9}-2\frac{5}{9} = 10\frac{8}{9}$$
5. $$8\frac{5}{6}+3\frac{5}{6}-7 = 5\frac{2}{3}$$
6. $$8-3\frac{4}{15}+6\frac{7}{15} = 11\frac{1}{5}$$