Решите систему неравенств: (x^2-4)/(3x^2+2)>0; (3x-3)/(x^2+x-12)<0.

\[\left\{ \begin{matrix}
x^{2} - 4 > 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
\frac{3 \cdot (x - 1)}{(x + 4)(x - 3)} < 0 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
(x - 2)(x + 2) > 0 \\
\frac{3 \cdot (x - 1)}{(x + 4)(x - 3)} < 0 \\
\end{matrix} \right.\ \]

\[Ответ:( - \infty;\ - 4) \cup (2;3)\text{.\ }\]