Решите систему уравнений: 1/x-1/y=1/12; 2x-y=2.

\[12 \cdot (x - 1) - 6x = x(x - 1)\]

\[12x - 12 - 6x = x^{2} - x\]

\[x^{2} - x - 6x + 12 = 0\]

\[x^{2} - 7x + 12 = 0\]

\[x_{1} + x_{2} = 7;\ \ \ \ x_{1} \cdot x_{2} = 12\]

\[x_{1} = 3;\ \ \ x_{2} = 4.\]

\[\left\{ \begin{matrix}
x = 3 \\
y = 4 \\
\end{matrix} \right.\ \ \ \ \ \ \ \ или\ \ \ \ \ \left\{ \begin{matrix}
x = 4 \\
y = 6 \\
\end{matrix} \right.\ \]

\[Ответ:(3;4);\ \ (4;6).\]