Решите систему уравнений: 2x-3y=-12; x+2y=1.

\[\left\{ \begin{matrix}
2x - 3y = - 12\ \ \\
x + 2y = 1\ \ \ | \cdot 2 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
2x - 3y = - 12 \\
2x + 4y = 2\ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ }( - )\]

\[- 7y = - 14\]

\[y = 2.\]

\[\left\{ \begin{matrix}
x = 1 - 2y \\
y = 2\ \ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\left\{ \begin{matrix}
x = 1 - 4 \\
y = 2\ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ }\left\{ \begin{matrix}
x = - 3 \\
y = 2\ \ \ \\
\end{matrix} \right.\ \ \]

\[Ответ:( - 3;2).\]