Решите систему уравнений: x^2+2y=6; y=x-1.

\[x^{2} + 2x - 2 - 6 = 0\]

\[x^{2} + 2x - 8 = 0\]

\[D_{1} = 1 + 8 = 9\]

\[x_{1} = - 1 + 3 = 2;\ \ \]

\[x_{2} = - 1 - 3 = - 4.\]

\[\left\{ \begin{matrix}
x = 2 \\
y = 1 \\
\end{matrix} \right.\ \ \ \ \ \ \ или\ \ \ \ \ \left\{ \begin{matrix}
x = - 4 \\
y = - 5 \\
\end{matrix} \right.\ \]

\[Ответ:(2;1);( - 4; - 5).\]