Вопрос:

Решите уравнение: 4) $$3\frac{1}{6} - (x + 1\frac{1}{12}) = 0$$ 5) $$6\frac{5}{27} - (x - 1\frac{2}{9}) = 3$$ 6) $$3\frac{5}{36} - (1\frac{4}{9} - x) = 1\frac{1}{12}$$

Ответ:

Решим уравнения. 4) $$3\frac{1}{6} - (x + 1\frac{1}{12}) = 0$$ $$3\frac{1}{6} - x - 1\frac{1}{12} = 0$$ $$-x = -3\frac{1}{6} + 1\frac{1}{12}$$ $$-x = -3\frac{2}{12} + 1\frac{1}{12}$$ $$-x = -2\frac{1}{12}$$ $$x = 2\frac{1}{12}$$ $$x = \frac{25}{12}$$ Ответ: $$x = \frac{25}{12}$$ 5) $$6\frac{5}{27} - (x - 1\frac{2}{9}) = 3$$ $$6\frac{5}{27} - x + 1\frac{2}{9} = 3$$ $$-x = -6\frac{5}{27} - 1\frac{2}{9} + 3$$ $$-x = -6\frac{5}{27} - 1\frac{6}{27} + 3$$ $$-x = -7\frac{11}{27} + 3$$ $$-x = -4\frac{11}{27}$$ $$x = 4\frac{11}{27}$$ $$x = \frac{119}{27}$$ Ответ: $$x = \frac{119}{27}$$ 6) $$3\frac{5}{36} - (1\frac{4}{9} - x) = 1\frac{1}{12}$$ $$3\frac{5}{36} - 1\frac{4}{9} + x = 1\frac{1}{12}$$ $$x = -3\frac{5}{36} + 1\frac{4}{9} + 1\frac{1}{12}$$ $$x = -3\frac{5}{36} + 1\frac{16}{36} + 1\frac{3}{36}$$ $$x = -3\frac{5}{36} + 2\frac{19}{36}$$ $$x = -2\frac{41}{36} + 2\frac{19}{36}$$ $$x = \frac{-41 + 19}{36}$$ $$x = \frac{-22}{36}$$ $$x = -\frac{11}{18}$$ Ответ: $$x = -\frac{11}{18}$$
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