Решение:
- $$4\frac{5}{7}(x-6\frac{3}{7})=2\frac{6}{7}$$
$$\frac{33}{7}(x-\frac{45}{7}) = \frac{20}{7}$$
$$x-\frac{45}{7} = \frac{20}{7} : \frac{33}{7} = \frac{20}{7} \cdot \frac{7}{33} = \frac{20}{33}$$
$$x = \frac{20}{33} + \frac{45}{7}$$
$$x = \frac{20 \cdot 7 + 45 \cdot 33}{33 \cdot 7} = \frac{140 + 1485}{231} = \frac{1625}{231} = 7\frac{8}{231}$$
- $$19\frac{28}{34}-(m+2\frac{20}{34})=12\frac{15}{34}$$
$$m+2\frac{20}{34} = 19\frac{28}{34} - 12\frac{15}{34}$$
$$m + 2\frac{20}{34} = (19-12) + (\frac{28}{34} - \frac{15}{34}) = 7 + \frac{13}{34} = 7\frac{13}{34}$$
$$m = 7\frac{13}{34} - 2\frac{20}{34} = (7-2) + (\frac{13}{34} - \frac{20}{34}) = 5 - \frac{7}{34} = 4\frac{34}{34} - \frac{7}{34} = 4\frac{27}{34}$$
- $$32-x=9\frac{18}{35}$$
$$x=32-9\frac{18}{35}$$
$$x = 32-9 - \frac{18}{35} = 23 - \frac{18}{35} = 22\frac{35}{35} - \frac{18}{35} = 22\frac{17}{35}$$
Ответ: 1) $$7\frac{8}{231}$$; 2) $$4\frac{27}{34}$$; 3) $$22\frac{17}{35}$$.